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3(-2x-3)-2^(2)=-(-3x-5)-2
We move all terms to the left:
3(-2x-3)-2^(2)-(-(-3x-5)-2)=0
We add all the numbers together, and all the variables
3(-2x-3)-(-(-3x-5)-2)-4=0
We multiply parentheses
-6x-(-(-3x-5)-2)-9-4=0
We calculate terms in parentheses: -(-(-3x-5)-2), so:We add all the numbers together, and all the variables
-(-3x-5)-2
We get rid of parentheses
3x+5-2
We add all the numbers together, and all the variables
3x+3
Back to the equation:
-(3x+3)
-6x-(3x+3)-13=0
We get rid of parentheses
-6x-3x-3-13=0
We add all the numbers together, and all the variables
-9x-16=0
We move all terms containing x to the left, all other terms to the right
-9x=16
x=16/-9
x=-1+7/9
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